通过将矩阵传递给函数来乘以两个矩阵的 C 程序

要理解此示例,您应该具备以下 C 语言编程主题的知识:

该程序要求用户输入矩阵的大小(行和列)。

然后,它要求用户输入这些矩阵的元素,最后添加并显示结果。

要执行此任务,需要执行三个功能:

  1. 从用户获取矩阵元素 enterData()
  2. 将两个矩阵相乘 multiplyMatrices()
  3. 显示乘法后的结果矩阵 display()

示例:通过将矩阵传递给函数来乘以矩阵

#include <stdio.h>

void enterData(int firstMatrix[][10], int secondMatrix[][10], int rowFirst, int columnFirst, int rowSecond, int columnSecond);
void multiplyMatrices(int firstMatrix[][10], int secondMatrix[][10], int multResult[][10], int rowFirst, int columnFirst, int rowSecond, int columnSecond);
void display(int mult[][10], int rowFirst, int columnSecond);

int main()
{
  int firstMatrix[10][10], secondMatrix[10][10], mult[10][10], rowFirst, columnFirst, rowSecond, columnSecond, i, j, k;

  printf("Enter rows and column for first matrix: ");
  scanf("%d %d", &rowFirst, &columnFirst);

  printf("Enter rows and column for second matrix: ");
  scanf("%d %d", &rowSecond, &columnSecond);

  // If colum of first matrix in not equal to row of second matrix, asking user to enter the size of matrix again.
  while (columnFirst != rowSecond)
  {
    printf("Error! column of first matrix not equal to row of second.\n");
    printf("Enter rows and column for first matrix: ");
    scanf("%d%d", &rowFirst, &columnFirst);
    printf("Enter rows and column for second matrix: ");
    scanf("%d%d", &rowSecond, &columnSecond);
  }

  // Function to take matrices data
        enterData(firstMatrix, secondMatrix, rowFirst, columnFirst, rowSecond, columnSecond);

        // Function to multiply two matrices.
        multiplyMatrices(firstMatrix, secondMatrix, mult, rowFirst, columnFirst, rowSecond, columnSecond);

        // Function to display resultant matrix after multiplication.
        display(mult, rowFirst, columnSecond);

  return 0;
}

void enterData(int firstMatrix[][10], int secondMatrix[][10], int rowFirst, int columnFirst, int rowSecond, int columnSecond)
{
  int i, j;
  printf("\nEnter elements of matrix 1:\n");
  for(i = 0; i < rowFirst; ++i)
  {
    for(j = 0; j < columnFirst; ++j)
    {
      printf("Enter elements a%d%d: ", i + 1, j + 1);
      scanf("%d", &firstMatrix[i][j]);
    }
  }

  printf("\nEnter elements of matrix 2:\n");
  for(i = 0; i < rowSecond; ++i)
  {
    for(j = 0; j < columnSecond; ++j)
    {
      printf("Enter elements b%d%d: ", i + 1, j + 1);
      scanf("%d", &secondMatrix[i][j]);
    }
  }
}

void multiplyMatrices(int firstMatrix[][10], int secondMatrix[][10], int mult[][10], int rowFirst, int columnFirst, int rowSecond, int columnSecond)
{
  int i, j, k;

  // Initializing elements of matrix mult to 0.
  for(i = 0; i < rowFirst; ++i)
  {
    for(j = 0; j < columnSecond; ++j)
    {
      mult[i][j] = 0;
    }
  }

  // Multiplying matrix firstMatrix and secondMatrix and storing in array mult.
  for(i = 0; i < rowFirst; ++i)
  {
    for(j = 0; j < columnSecond; ++j)
    {
      for(k=0; k<columnFirst; ++k)
      {
        mult[i][j] += firstMatrix[i][k] * secondMatrix[k][j];
      }
    }
  }
}

void display(int mult[][10], int rowFirst, int columnSecond)
{
  int i, j;
  printf("\nOutput Matrix:\n");
  for(i = 0; i < rowFirst; ++i)
  {
    for(j = 0; j < columnSecond; ++j)
    {
      printf("%d  ", mult[i][j]);
      if(j == columnSecond - 1)
        printf("\n\n");
    }
  }
}

输出

Enter rows and column for first matrix: 3
2
Enter rows and column for second matrix: 3
2
Error! column of first matrix not equal to row of second.

Enter rows and column for first matrix: 2
3
Enter rows and column for second matrix: 3
2

Enter elements of matrix 1:
Enter elements a11: 3
Enter elements a12: -2
Enter elements a13: 5
Enter elements a21: 3
Enter elements a22: 0
Enter elements a23: 4

Enter elements of matrix 2:
Enter elements b11: 2
Enter elements b12: 3
Enter elements b21: -9
Enter elements b22: 0
Enter elements b31: 0
Enter elements b32: 4

Output Matrix:
24  29

6  25